A body is released from a height equal to the radius (R) of the earth. The velocity of…
Physics · JEE Main · NTA Exams — Gravitation
A body is released from a height equal to the radius (R) of the earth. The velocity of the body when it strikes the surface of the earth will be
- \(\sqrt{g R}\)
- \(\sqrt{2 g R}\)
- \(2 \sqrt{2 g R}\)
- \(2 \sqrt{g R}\)
Answer
(A) g R
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