Radius of orbit of satellite of earth is R. Its Kinetic energy is proportional to:

Physics · JEE Main · NTA ExamsGravitation

Radius of orbit of satellite of earth is R. Its Kinetic energy is proportional to:
  1. \(\frac{1}{R}\)
  2. \(\frac{1}{\sqrt{R}}\)
  3. R
  4. \(\frac{1}{R^{\frac{3}{2}}}\)

Answer

(A) 1 R

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Gravitation questions · Browse all practice questions