A conducting wire of parabolic shape, y = x 2 , is moving with velocity V =V_ 0 i in a…
Physics · JEE Advanced · NTA Exams — Electromagnetic Induction and Alternating Currents
A conducting wire of parabolic shape, y = x2, is moving with velocity \(\vec{V}=V_{0} \hat{i}\) in a non-uniform magnetic field \(\vec{B}=B_{0}\left(1+\left(\frac{y}{L}\right)^{\beta}\right) \hat{k}\) as shown
in figure. If V0, B0, L and β are positive constants and Δφ is the potential difference developed between the ends of the wire, then the correct statement(s)
is/are
in figure. If V0, B0, L and β are positive constants and Δφ is the potential difference developed between the ends of the wire, then the correct statement(s)
is/are
- |Df| remains same if the parabolic wire is replaced by a straight wire, y = x initially, of length
L 
- |Df| is proportional to the length of wire projected on the y-axis.
Answer
(C)
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