The magnetic field within a long, straight solenoid with a circular cross section and…
Physics · JEE Advanced · NTA Exams — Electromagnetic Induction and Alternating Currents
The magnetic field within a long, straight solenoid with a circular cross section and radius R is increasing at a rate of dB/dt.
What is the rate of change of flux through a circle with radius r1 inside the solenoid, normal to the axis of the solenoid, and with centre on the solenoid axis is
- \(\sqrt{2} \pi \mathrm{r}_{1}^{2} \frac{\mathrm{~dB}}{\mathrm{dt}}\)
- \(\frac{1}{2} \pi \mathrm{r}_{1}^{2} \frac{\mathrm{~dB}}{\mathrm{dt}}\)
- \(\pi \mathrm{r}_{1}^{2} \frac{\mathrm{~dB}}{\mathrm{dt}}\)
- \(\frac{3}{2} \pi \mathrm{r}_{1}^{2} \frac{\mathrm{~dB}}{\mathrm{dt}}\)
Answer
(B) 1 2 r _ 1 ^ 2 ~dB dt
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