If the tangent at each point of the curve y = 2 3 x 3 – 2ax 2 + 2x + 5 makes an acute…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If the tangent at each point of the curve
y = \(\frac{2}{3}\) x3 – 2ax2 + 2x + 5 makes an acute angle with the positive direction of x-axis, then
y = \(\frac{2}{3}\) x3 – 2ax2 + 2x + 5 makes an acute angle with the positive direction of x-axis, then
- a ≥ 1
- –1 ≤ a ≤ 1
- a ≤ – 1
- none of these
Answer
(B) –1 ≤ a ≤ 1
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