_ h 0 2 [ 3 ( 6 +h )- ( 6 +h ) ] 3 h( 3 )
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
\[\lim _{h \rightarrow 0} \frac{2\left[\sqrt{3} \sin \left(\frac{\pi}{6}+h\right)-\cos \left(\frac{\pi}{6}+h\right)\right]}{\sqrt{3} h(\sqrt{3} \cosh \sinh )}\]
- -2/3
- -3/4
- -2\(\sqrt{ }\)
- 4/3
Answer
(D) 4/3
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