The equation of a line through the point of intersection of the lines x – 3y + 1 = 0 and…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of a line through the point of intersection of the lines x – 3y + 1 = 0 and 2x + 5y – 9 = 0 and whose distance from the origin is \(\sqrt{5}\) is
- 2x + y – 5 = 0
- 2x – y + 5 = 0
- 2x + y – 10 = 0
- 2x – y – 10
Answer
(A) 2x + y – 5 = 0
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