ABCD is a trapezium such that AB and CD are parallel and BC ⊥ CD. If ∠ADB = θ, BC = p and…
Mathematics · JEE Main · NTA Exams — Trigonometry
ABCD is a trapezium such that AB and CD are parallel and BC ⊥ CD. If ∠ADB = θ, BC = p and CD = q, then AB is equal to
- \(\frac{\left(p^{2}+q^{2}\right) \sin \theta}{p \cos \theta+q \sin \theta}\)
- \(\frac{p^{2}+q^{2}}{p^{2} \cos \theta+q^{2} \sin \theta}\)
- \(\frac{\left(p^{2}+q^{2}\right) \sin \theta}{(p \cos \theta+q \sin \theta)^{2}}\)
Answer
(A) (p^ 2 +q^ 2 ) p +q
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