If A > 0, B > 0 and A + B = 3 , then the maximum value of tan A tan B is
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If A > 0, B > 0 and A + B \(=\frac{\pi}{3},\) then the maximum value of
tan A tan B is
tan A tan B is
- \(\frac{1}{\sqrt{3}}\)
- \(\frac{1}{3}\)
- 3
- \(\sqrt{3}\)
Answer
(B) 1 3
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