Radius of orbit of a satellite of the Earth is R. Its kinetic energy is proportional to
Physics · JEE Main · NTA Exams — Gravitation
Radius of orbit of a satellite of the Earth is R. Its kinetic energy is proportional to
- \(\frac{1}{\mathrm{R}}\)
- \(\frac{1}{\sqrt{R}}\)
- \(\text { R }\)
- \(\frac{1}{R^{\frac{3}{2}}}\)
Answer
(A) 1 R
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