The value of _ -2 ^ 2 [p ( 1+x 1-x )+q ( 1-x 1+x )^ -2 +r ] d x depends on
Mathematics · JEE Main · NTA Exams — Integral Calculus
The value of \(\int_{-2}^{2}\left[p \log \left(\frac{1+x}{1-x}\right)+q \log \left(\frac{1-x}{1+x}\right)^{-2}+r\right] d x\) depends on
- the value of p
- the value of q
- the value of r
- the value of p and q
Answer
(C) the value of r
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let T > 0 be a fixed real number. Suppose f is a continuous function such that for all x ∈ R, f(x+T)=f(x) …
- The area of the region described by A = (x, y) : x 2 + y 2 ≤ 1 and y 2 ≤ 1 – x is
- 1+ x 1- x d x equals
- If 1 (3-5 x)(2+3 x) = A 3-5 x + B 2+3 x , then A : B is
- If I _ n = _ 0 ^ / 4 ^ n d where n is a positive integer, then n (I_ n-1 +I_ n+1 ) is equal to
- Statement - 1: x x d x (x > 0) can not be evaluated. Statement - 2: Only differentiable functions can be…
- If f(x)= _ 1 ^ x^ 3 d t 1+t^ 4 then f^ (x) is equal to
- I_ 1 = _ 1 ^ 2 e^ x d x and I_ 2 = _ 1 ^ 2 _ e x d x Then
More Integral Calculus questions · Browse all practice questions