The lines y = - 3 2 x and y=- 2 5 x intersect the curve 3x 2 + 4xy + 5y 2 – 4 = 0 at the…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The lines y = \(-\frac{3}{2} x\) and \(y=-\frac{2}{5} x\) intersect the curve
3x2 + 4xy + 5y2 – 4 = 0 at the points P and Q respectively. The tangents drawn to the curve at P and Q
3x2 + 4xy + 5y2 – 4 = 0 at the points P and Q respectively. The tangents drawn to the curve at P and Q
- intersect each other at angle of 45°
- are parallel to each other
- are perpendicular to each other
- none of these
Answer
(C) are perpendicular to each other
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