The value of _ x (x+1)(3 x+4) x^ 2 (x-8) is equal to

Mathematics · JEE Main · NTA ExamsLimit, Continuity and Differentiability

The value of \(\lim _{x \rightarrow \infty} \frac{(x+1)(3 x+4)}{x^{2}(x-8)}\) is equal to
  1. 1/5
  2. 1/6
  3. 1/4
  4. 1/2

Answer

(B) 1/6

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