The value of _ x (x+1)(3 x+4) x^ 2 (x-8) is equal to
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The value of \(\lim _{x \rightarrow \infty} \frac{(x+1)(3 x+4)}{x^{2}(x-8)}\) is equal to
- 1/5
- 1/6
- 1/4
- 1/2
Answer
(B) 1/6
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