_ h 0 2 [ 3 ( 6 +h )- ( 6 +h ) ] 3 h( 3 h- h) is equal to
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
\[\lim _{h \rightarrow 0} \frac{2\left[\sqrt{3} \sin \left(\frac{\pi}{6}+h\right)-\cos \left(\frac{\pi}{6}+h\right)\right]}{\sqrt{3} h(\sqrt{3} \cos h-\sinh h)}\] is equal to
- 4/3
- – 4/3
- 2/3
- 3/4
Answer
(A) 4/3
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