_ n 1 n (1+e^ 1 / n +e^ 2 / n + +e^ n-1 n ) is equal to
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
\(\lim _{n \rightarrow \infty} \frac{1}{n}\left(1+e^{1 / n}+e^{2 / n}+\ldots+e^{\frac{n-1}{n}}\right)\) is equal to
- e
- –e
- e – 1
- 1 – e
Answer
(C) e – 1
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let f : R → R be a differentiable function and f (1) = 4. Then the value of _ x 1 1 x-1 _ 4 ^ f(x) 2 t d t is
- If _ x 0 ((a-n) n x- x) n x x^ 2 =0, where n is non zero real number, then a is equal to
- where [.] denotes greatest integer function, is equal to
- For each t ∈ R , let [ t ] be the greatest integer less than or equal to t . Then _ x 0^ + x ( [ 1 x ]+ [ 2 x…
- If f (x) = sin ( 2 [x]-x^ 5 ), 1 is equal to
- If f is a differentiable function satisfying = 0 for all n ≥ 1, n ∈ I , then
- Let L= _ x 0 a- a^ 2 -x^ 2 - x^ 2 4 x^ 4 , a>0 . If L is finite, then
- Let f : R R be a function such that and f ′ (0) = 3 . Then
More Limit, Continuity and Differentiability questions · Browse all practice questions