If f (x) = sin ( 2 [x]-x^ 5 ), 1 is equal to

Mathematics · JEE Advanced · NTA ExamsLimit, Continuity and Differentiability

If f (x) = sin \(\left(\frac{\pi}{2}[x]-x^{5}\right), 1 is equal to
  1. \(5\left(\frac{\pi}{2}\right)^{4 / 5}\)
  2. \(-5\left(\frac{\pi}{2}\right)^{4 / 5}\)
  3. 0
  4. None of these

Answer

(B) -5 ( 2 )^ 4 / 5

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