If f (x) = sin ( 2 [x]-x^ 5 ), 1 is equal to
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
If f (x) = sin \(\left(\frac{\pi}{2}[x]-x^{5}\right), 1 is equal to
- \(5\left(\frac{\pi}{2}\right)^{4 / 5}\)
- \(-5\left(\frac{\pi}{2}\right)^{4 / 5}\)
- 0
- None of these
Answer
(B) -5 ( 2 )^ 4 / 5
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