If y = ( ax + b cx + d ), then 2 dy dx ~d ^ 3 y dx ^ 3 is equal to
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
If y = \(\left(\frac{\mathrm{ax}+\mathrm{b}}{\mathrm{cx}+\mathrm{d}}\right),\) then 2 \(\frac{\mathrm{dy}}{\mathrm{dx}} \cdot \frac{\mathrm{~d}^{3} \mathrm{y}}{\mathrm{dx}^{3}}\) is equal to
- \(\left(\frac{d^{2} y}{d x^{2}}\right)^{2}\)
- \(3 \frac{\mathrm{~d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}\)
- \(3\left(\frac{\mathrm{~d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}\right)^{2}\)
- \(3 \frac{\mathrm{~d}^{2} \mathrm{x}}{\mathrm{dy}^{2}}\)
Answer
(C) 3 ( ~d ^ 2 y dx ^ 2 )^ 2
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