_ n 1 n _ r=1 ^ 2 n r n^ 2 +r^ 2
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
\(\lim _{n \rightarrow \infty} \frac{1}{n} \sum_{r=1}^{2 n} \frac{r}{\sqrt{n^{2}+r^{2}}}\)
Answer
(B)
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