The potential energy of a particle of mass 0.1kg, moving along the x-axis, is given by U…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
The potential energy of a particle of mass 0.1kg, moving along the x-axis, is given by U = 5x(x – 4)J, where x is in meter. It can be concluded that
- the particle is acted upon by a constant force.
- the speed of the particle is maximum at x = 2 m.
- the particle executes SHM.
- the period of oscillation of the particle is \(\frac{\pi}{5} \mathrm{~s}\).
Answer
(B) the speed of the particle is maximum at x = 2 m., (C) the particle executes SHM., (D) the period of oscillation of the particle is 5 ~s .
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