A particle is executing simple harmonic motion with a period of T seconds and amplitude a…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre. The shortest time it takes to reach a point \(\frac{a}{\sqrt{2}} m\) from its mean position in seconds is
- T
- \(\frac{T}{4}\)
- \(\frac{T}{8}\)
- \(\frac{T}{16}\)
Answer
(C) T 8
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