Given two straight lines x – y – 7 = 0 and x – y + 3 = 0. Equation of a line which…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
Given two straight lines x – y – 7 = 0 and x – y + 3 = 0. Equation of a line which divides the distance between them in the ratio 3 : 2 can be and || to them.
- x – y – 1 = 0
- x – y – 3 = 0
- y = x
- x – y + 1 = 0
Answer
(A) x – y – 1 = 0, (B) x – y – 3 = 0
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If A (3,4) and B is a variable point on the lines |x| = 6. If AB 4 then the number of positions of B with…
- The diagonals of a parallelogram PQRS are along the lines x + 3 y = 4 and 6 x – 2 y = 7. Then PQRS must be a
- A line meets the co-ordinate axes in A & B. A circle is circumscribed about the triangle OAB. If d 1 and d 2…
- The locus of the mid point of the chords of the circle x 2 + y 2 = a 2 , which are tangent to the hyperbola…
- The circumference of the circle x 2 + y 2 – 2x + 8y – q = 0 is bisected by the circle x 2 + y 2 + 4x + 12y +…
- The two parabola y 2 = 4ax and y 2 = 4c (x –b) cannot have a common normal, other than the axis unless, if
- The co-ordinates of a point P on the line 2x – y + 5 = 0 such that |PA – PB| is maximum where A is (4, –2)…
- Let PQ and RS be tangents at the extremities of the diameter PR of a circle of radius r . If PS and RQ…
More Co-ordinate Geometry questions · Browse all practice questions