The circumference of the circle x 2 + y 2 – 2x + 8y – q = 0 is bisected by the circle x 2…

Mathematics · JEE Advanced · NTA ExamsCo-ordinate Geometry

The circumference of the circle x2 + y2 – 2x + 8y – q = 0 is bisected by the circle x2 + y2 + 4x + 12y + p = 0, then
p + q is equal to :
  1. 25
  2. 100
  3. 10
  4. 48

Answer

(C) 10

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