A light beam emanating from the point A(3, 10) reflects from the straight line 2x + y – 6…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
A light beam emanating from the point A(3, 10) reflects from the straight line 2x + y – 6 = 0 and then passes through the point B(4, 3). The equation of the reflected beam is :
- 3x – y + 1 = 0
- x + 3y – 13 = 0
- 3x + y – 15 = 0
- x – 3y + 5 = 0
Answer
(A) 3x – y + 1 = 0
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If the locus of the circumcentre of a variable triangle having sides y–axis, y = 2 and l x + my = 1, where (…
- A right angle triangle ABC having ‘C’ a right angle has AC = a and BC = b units. The points A and B slide…
- If L ≡ 2x + y – 6 = 0, then the locus of circumcentre of ∆PQR is P is a variable point on the line L = 0 …
- Area of the quadrilateral formed by the lines | x | + | y | = 2 is :
- The abscissa of two points A and B are the roots of the equation x 2 + 2ax – b 2 = 0 and their ordinates are…
- Let OX and OY be two fixed lines inclined at a constant angle α. A variable line cuts OX at P and OY at Q…
- The equation of the common tangents to the parabola y 2 = 8x and the hyperbola 3x 2 – y 2 = 3 is-
- The equation of the line segment AB is y = x. If A and B lie on the same side of the line mirror 2x – y = 1…
More Co-ordinate Geometry questions · Browse all practice questions