The abscissa of two points A and B are the roots of the equation x 2 + 2ax – b 2 = 0 and…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
The abscissa of two points A and B are the roots of the equation x2 + 2ax – b2 = 0 and their ordinates are the roots of the equation y2 + 2 py – q2 = 0. The radius of the circle with AB as a diameter will be-
- \(\sqrt{a^{2}+b^{2}+p^{2}+q^{2}}\)
- \(\sqrt{b^{2}+q^{2}}\)
- \(\sqrt{a^{2}+b^{2}-p^{2}-q^{2}}\)
- \(\sqrt{a^{2}+p^{2}}\)
Answer
(A) a^ 2 +b^ 2 +p^ 2 +q^ 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- AB, AC are tangents to a parabola y 2 = 4ax. p 1 , p 2 and p 3 are the lengths of the perpendiculars from A…
- The straight lines x + y = 0, 3x + y – 4 = 0, x + 3y – 4 = 0 form a triangle which is :
- The correct matching is :
- Let P = (1, 1) and Q = (3, 2). The point R on the x-axis such that PR + RQ is the minimum is
- If the straight line x + y = 1 is a normal to the parabola x 2 = ay, then the value of a is
- P is a variable point on the line L = 0 . Tangents are drawn to the circle x 2 + y 2 = 4 from P to touch it…
- The distance from the centre of the circle x² + y² = 2x to the straight line passing through the points of…
- Consider a circle with its centre lying on the focus of the parabola, y 2 = 2 px (p > 0) such that it touches…
More Co-ordinate Geometry questions · Browse all practice questions