Concentration CN – in 0.1 M HCN is [K a = 4 × 10 –10 ]
Chemistry · JEE Main · NTA Exams — Equilibrium
Concentration CN– in 0.1 M HCN is [Ka = 4 × 10–10]
- 2.5 × 10–6 M
- 4.5 × 10–6 M
- 6.3 × 10–6 M
- 9.2 × 10–6 M
Answer
(C) 6.3 × 10 –6 M
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