For a “c molar” concentrated solution of a weak electrolyte A x B y , the degree of…
Chemistry · JEE Main · NTA Exams — Equilibrium
For a “c molar” concentrated solution of a weak electrolyte AxBy, the degree of dissociation is given as
- \(\alpha=\sqrt{\mathrm{K}_{\mathrm{eq}} / \mathrm{c}(\mathrm{x}+\mathrm{y})}\)
- \(\alpha=\sqrt{\mathrm{K}_{\mathrm{eq}} \mathrm{c} /(\mathrm{xy})}\)
- \(\alpha=\left(\mathrm{K}_{\mathrm{eq}} / \mathrm{c}^{\mathrm{x}+\mathrm{y}-1} \mathrm{x}^{\mathrm{x}} \mathrm{y}^{\mathrm{y}}\right)^{\mathrm{l} /(\mathrm{x}+\mathrm{y})}\)
- \(\sqrt{\mathrm{K}_{\mathrm{eq}} / \mathrm{xyc}}\)
Answer
(C) = ( K _ eq / c ^ x + y -1 x ^ x y ^ y )^ l /( x + y )
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