For a fairly concentrated solution of a weak electrolyte A x B y , the degree of…

Chemistry · JEE Main · NTA ExamsEquilibrium

For a fairly concentrated solution of a weak electrolyte AxBy, the degree of dissociation is given by:
  1. \(x=\sqrt{\frac{K_{\mathrm{Eq}} x y}{c}}\)
  2. \(x=\sqrt{\frac{K_{\mathrm{Rq}} D}{\mathrm{xy}}}\)
  3. \(x=\sqrt{\frac{K_{\mathrm{Eq}}}{\mathrm{C}(x+\mathrm{y})}}\)
  4. \(x=\left(\frac{K_{\mathrm{Eq}}}{\Gamma^{\mathrm{x}+\mathrm{y}-1} \mathrm{x}^{\mathrm{x}} \mathrm{y}^{\mathrm{y}}}\right)^{1 /(\mathrm{x}+\mathrm{y})}\)

Answer

(D) x= ( K_ Eq ^ x + y -1 x ^ x y ^ y )^ 1 /( x + y )

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