Ka 1 , Ka 2 and Ka 3 are the respective ionization constants for the following reactions…
Chemistry · JEE Main · NTA Exams — Equilibrium
Ka1, Ka2 and Ka3 are the respective ionization constants for the following reactions (a ), (b ), and (c ). (JEE Main 2022)
(a ) H2C2O4 \(\text { ⇌ }\) H+ + HC2O4–
(b ) HC2O4– \(\text { ⇌ }\) H+ + C2O42–
(c ) H2C2O4 \(\text { ⇌ }\) 2H+ + C2O42–
The relationship between Ka1, Ka2 and Ka3 is given as
(a ) H2C2O4 \(\text { ⇌ }\) H+ + HC2O4–
(b ) HC2O4– \(\text { ⇌ }\) H+ + C2O42–
(c ) H2C2O4 \(\text { ⇌ }\) 2H+ + C2O42–
The relationship between Ka1, Ka2 and Ka3 is given as
- Ka3 = Ka1 + Ka2
- Ka3 = Ka1 – Ka2
- Ka3 = Ka1 / Ka2
- Ka3 = Ka1 x Ka2
Answer
(D) Ka 3 = Ka 1 x Ka 2
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