The equilibrium constant (K p ) for the decomposition of gaseous H 2 O H 2 O (g) ⇌ H 2…
Chemistry · JEE Main · NTA Exams — Equilibrium
The equilibrium constant (Kp) for the decomposition of gaseous H2O
H2O (g) \(\text { ⇌ }\) H2 (g) + \(\frac{1}{2}\) O2(g)
is related to degree of dissociation (α) at a total pressure p, given by
H2O (g) \(\text { ⇌ }\) H2 (g) + \(\frac{1}{2}\) O2(g)
is related to degree of dissociation (α) at a total pressure p, given by
- \[K_{p}=\frac{\alpha^{3} p^{1 / 2}}{(1+\alpha)(2+\alpha)^{1 / 2}}\]
- \(K_{p}=\frac{\alpha^{3} p^{3 / 2}}{(1-\alpha)(2+\alpha)^{1 / 2}}\)
- \(K_{p}=\frac{\alpha^{3 / 2} p^{2}}{(1-\alpha)(2+\alpha)^{1 / 2}}\)
- \(K_{p}=\frac{\alpha^{3 / 2} p^{1 / 2}}{(1-\alpha)(2+\alpha)^{1 / 2}}\)
Answer
(D) K_ p = ^ 3 / 2 p^ 1 / 2 (1- )(2+ )^ 1 / 2
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