For the reversible reaction, N 2 (g) + 3H 2 (g) ⇌ 2NH 3 (g) at 500°C, the value of K p is…
Chemistry · JEE Main · NTA Exams — Equilibrium
For the reversible reaction,
N2(g) + 3H2(g) \(\text { ⇌ }\) 2NH3(g)
at 500°C, the value of Kp is 1.44 × 10–5 when partial pressure is measured in atmosphere. The corresponding value of Kc with concentration in mole litre-1, is
N2(g) + 3H2(g) \(\text { ⇌ }\) 2NH3(g)
at 500°C, the value of Kp is 1.44 × 10–5 when partial pressure is measured in atmosphere. The corresponding value of Kc with concentration in mole litre-1, is
- 1.44 × 10–5/(0.082 × 500)–2
- 1.44 × 10–5/(8.314 × 773)–2
- 1.44 × 10–5/(0.082 × 773)2
- 1.44 × 10–5/(0.082 × 773)–2
Answer
(D) 1.44 × 10 –5 /(0.082 × 773) –2
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