Let f 1 (n) = 1 + 1 2 + 1 3 + + 1 n , then f 1 (1) + f 1 (2) + f 1 (3) + ... + f 1 (n) is…
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
Let f1 (n) = 1\(+\frac{1}{2}+\frac{1}{3}+\ldots+\frac{1}{n},\) then
f1(1) + f1(2) + f1(3) + ... + f1(n) is equal to :
f1(1) + f1(2) + f1(3) + ... + f1(n) is equal to :
- n f1(n) – 1
- (n + 1) f1(n) – n
- (n + 1) f1(n) + n
- n f1(n) + n
Answer
(B) (n + 1) f 1 (n) – n
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