The function f : [0, 3] → [1, 29], defined by f ( x ) = 2 x 3 –15 x 2 + 36 x + 1, is
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
The function f : [0, 3] → [1, 29], defined by
f(x) = 2x3 –15x2 + 36x + 1, is
f(x) = 2x3 –15x2 + 36x + 1, is
- one-one and onto
- onto but not one-one
- one-one but not onto
- neither one-one nor onto
Answer
(B) onto but not one-one
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