Solution of 2 x + 2 |x| > 2 2 is

Mathematics · JEE Advanced · NTA ExamsSets, Relations and Functions

Solution of 2x + 2|x| > 2\(\sqrt{2}\) is
  1. \(\left(-\infty, \log _{2}(\sqrt{2}+1)\right)\)
  2. \((0, \infty)\)
  3. \(\left(-\infty, \log _{2}(\sqrt{2}-1)\right] \cup[1 / 2, \infty)\)

Answer

(D) (- , _ 2 ( 2 -1) ] [1 / 2, )

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