Solution of 2 x + 2 |x| > 2 2 is
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
Solution of 2x + 2|x| > 2\(\sqrt{2}\) is
- \(\left(-\infty, \log _{2}(\sqrt{2}+1)\right)\)
- \((0, \infty)\)

- \(\left(-\infty, \log _{2}(\sqrt{2}-1)\right] \cup[1 / 2, \infty)\)
Answer
(D) (- , _ 2 ( 2 -1) ] [1 / 2, )
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