Let f : [- 3 , 2 3 ] be a function defined as f (x) = 3 sin x – cos x + 2 . The f –1 (x)…
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
Let f : \(\left[-\frac{\pi}{3}, \frac{2 \pi}{3}\right]\) be a function defined as
f (x) = \(\sqrt{3}\)sin x – cos x + 2 . The f –1 (x) is given by
f (x) = \(\sqrt{3}\)sin x – cos x + 2 . The f –1 (x) is given by
- \(\sin ^{-1}\left(\frac{x-2}{2}\right)-\frac{\pi}{6}\)
- \(\sin ^{-1}\left(\frac{x-2}{2}\right)+\frac{\pi}{6}\)
- \(\frac{2 \pi}{3}+\cos ^{-1}\left(\frac{x-2}{2}\right)\)
- none of these
Answer
(B) ^ -1 ( x-2 2 )+ 6
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