The rate law for a reaction between the substance A and B is given by rate = k [A] n [B]…
Chemistry · JEE Main · NTA Exams — Chemical Kinetics
The rate law for a reaction between the substance A and B is given by rate = k [A]n [B]m. On doubling the concentration of A and halving the conc. of B, the ratio of the new rate to the earlier rate of reaction will be
- \(\frac{1}{2^{m+n}}\)
- m + n
- n – m
- \(2^{(\mathrm{n}-\mathrm{m})}\)
Answer
(D) 2^ ( n - m )
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