The temperature dependence of the rate constant k is expressed as k = Ae ^ - E _ a / RT …
Chemistry · JEE Main · NTA Exams — Chemical Kinetics
The temperature dependence of the rate constant k is expressed as k = \(\mathrm{Ae}^{-\mathrm{E}_{a} / \mathrm{RT}} .\) When a plot between logk and 1/T is plotted we get the graph as shown. What is the value of slope in the graph ?
- \(\frac{\mathrm{E}_{\mathrm{a}}}{\mathrm{RT}}\)
- \(-\frac{\mathrm{E}_{\mathrm{a}}}{2.303 \mathrm{R}}\)
- \(-\frac{\mathrm{E}_{\mathrm{a}}}{2.303 \mathrm{RT}} \log \mathrm{~A}\)
- \(-\frac{\mathrm{E}_{\mathrm{a}}}{2.303} \frac{\mathrm{R}}{\mathrm{~T}}\)
Answer
(B) - E _ a 2.303 R
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