The thermal decomposition of acetaldehyde: CH _ 3 CHO CH _ 4 + CO _ 4 has rate constant…
Chemistry · JEE Main · NTA Exams — Chemical Kinetics
The thermal decomposition of acetaldehyde: \(\mathrm{CH}_{3} \mathrm{CHO} \longrightarrow \mathrm{CH}_{4}+\mathrm{CO}_{4}\) has rate constant of 1.8 × 10-3 mole-1/2 L1/2 min-1 at a given temperature. How would \(-\frac{d\left[\mathrm{CH}_{3}[\mathrm{CHO}]\right.}{d t}\) will change if concentration of acetaldehyde is doubled keeping the temperature constant?
- will increase by 2.828 times
- will increase by 11.313 times
- will not change
- will increase by 4 times
Answer
(A) will increase by 2.828 times
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