For the two gaseous reactions, following data are given A ~B ; k _ 1 =10^ 10 e ^ -20,000…
Chemistry · JEE Main · NTA Exams — Chemical Kinetics
For the two gaseous reactions, following data are given
\(\mathrm{A} \longrightarrow \mathrm{~B} ; \mathrm{k}_{1}=10^{10} \mathrm{e}^{-20,000 / \mathrm{T}}\)
\(\mathrm{C} \longrightarrow \mathrm{D} ; \mathrm{k}_{2}=10^{12} \mathrm{e}^{-24,606 / \mathrm{T}}\)
the temperature at which k1 becomes equal to k2 is
\(\mathrm{A} \longrightarrow \mathrm{~B} ; \mathrm{k}_{1}=10^{10} \mathrm{e}^{-20,000 / \mathrm{T}}\)
\(\mathrm{C} \longrightarrow \mathrm{D} ; \mathrm{k}_{2}=10^{12} \mathrm{e}^{-24,606 / \mathrm{T}}\)
the temperature at which k1 becomes equal to k2 is
- 400 K
- 1000 K
- 800 K
- 1500 K
Answer
(B) 1000 K
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