Let p= _ x 1^ + (1+ ^ 2 x )^ 1 2 x then log p is equal to:
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Let \(p=\lim _{x \rightarrow 1^{+}}\left(1+\tan ^{2} \sqrt{x}\right)^{\frac{1}{2 x}}\) then log p is equal to:
- 2
- 1
- \(\frac{1}{2}\)
- \(\frac{1}{4}\)
Answer
(D) 1 4
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