The derivative of ^ -1 ( x- x x+ x ) , with respect to x 2 , where x (0, 2 ) is:
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The derivative of \(\tan ^{-1}\left(\frac{\sin x-\cos x}{\sin x+\cos x}\right)\), with respect to \(\frac{\mathbf{x}}{2}\), where \(x \in\left(0, \frac{\pi}{2}\right)\) is:
- \(\frac{2}{3}\)
- 1
- 2
- \(\frac{1}{2}\)
Answer
(D) 1 2
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