Yield of NH 3 in Haber’s process N _ 2( ~g ) +3 H _ 2( ~g ) ⇌ 2NH 3(g) , ∆H = – 22 kcal…

Chemistry · JEE Advanced · NTA ExamsEquilibrium

Yield of NH3 in Haber’s process
\(\mathrm{N}_{2(\mathrm{~g})}+3 \mathrm{H}_{2(\mathrm{~g})}\)\(\text { ⇌ }\)2NH3(g), ∆H = – 22 kcal;
can be increased by
  1. compressing the reaction system
  2. raising the temperature
  3. decreasing the temperature
  4. using the catalyst to lower down the activation energy

Answer

(A) compressing the reaction system, (C) decreasing the temperature

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Equilibrium questions · Browse all practice questions