If I= _ 0 ^ / 2 e^ - x d x where (0, ), then
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
If \(I=\int_{0}^{\pi / 2} e^{-\alpha \sin x} d x\)where \(\alpha \in(0, \infty),\) then
- \(I<\frac{\pi}{2}\)
- \(I>\frac{\pi}{2}\left(e^{-\alpha}+1\right)\)
- \(I>\frac{\pi}{2} e^{-\alpha}\)
- \(I>0\)
Answer
(A) I< 2, (C) I> 2 e^ -, (D) I>0
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