Let f be a positive function. Let I_ 1 = _ 1-k ^ k x f[x(1-x)] d x I_ 2 = _ 1-k ^ k…
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
Let f be a positive function. Let \(I_{1}=\int_{1-k}^{k} x f[x(1-x)] d x\)
\(I_{2}=\int_{1-k}^{k} f[x(1-x)] d x\)where 2k – 1 > 0, Then
is
\(I_{2}=\int_{1-k}^{k} f[x(1-x)] d x\)where 2k – 1 > 0, Then
is- 2
- k
- 1/2
- 1
Answer
(C) 1/2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Using integral _ 0 ^ / 2 ( x) d x =- _ 0 ^ / 2 ( x) d x=- 2 2 _ 0 ^ / 2 ( x) d x=0 and _ 0 ^ / 4 (1+ x) d x=…
- The value of _ 0 ^ / 2 d x 1+ ^ 3 x is
- The value of _ - / 2 ^ / 2 x^ 2 x 1+e^ x d x is equal to
- The value of the integral ^ 3 x+ ^ 5 x ^ 2 x+ ^ 4 x d x is
- The function F(x)= _ / 6 ^ x (4 t+3 t) d t attains least value on [π/4, 3π/4] at x equals.
- Assertion : If 1 f(x) d x=2 log | f (x)|+c, then f(x)= x 2 Reason : When f (x) = x 2 , then 1 f(x) d x= 2 x d…
- _ 0 ^ 1 / 2 e^ x ( ^ -1 x- x (1-x^ 2 )^ 3 / 2 ) d x=
- Area of the region bounded by y e^ x and y x , is
More Integral Calculus questions · Browse all practice questions