If f(x)= _ ^ 2 / 16 ^ x^ 2 x t 1+ ^ 2 t d t then f^ ( ) is equal to
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
If \(f(x)=\int_{\pi^{2} / 16}^{x^{2}} \frac{\cos x \cos \sqrt{t}}{1+\sin ^{2} \sqrt{t}} d t\) then \(f^{\prime}(\pi)\) is equal to
- \(0\)
- \(\pi\)
- \(2 \pi\)
- \(\frac{\pi}{2}\)
Answer
(C) 2
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