_ 0 ^ 1 d x (5+2 x-2 x^ 2 ) (1-e^ 2-4 x ) =
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
\(\int_{0}^{1} \frac{d x}{\left(5+2 x-2 x^{2}\right)\left(1-e^{2-4 x}\right)}=\)
- \(\frac{1}{\sqrt{11}} \log _{e}\left(\frac{\sqrt{11}+2}{\sqrt{11}}\right)\)
- \(\frac{1}{\sqrt{11}} \log _{e}\left(\frac{\sqrt{11}+1}{\sqrt{10}}\right)\)
- \(\frac{1}{\sqrt{10}} \log _{e}\left(\frac{\sqrt{10}+2}{\sqrt{11}}\right)\)
- \(\frac{1}{\sqrt{10}} \log _{e}\left(\frac{\sqrt{10}+1}{\sqrt{11}}\right)\)
Answer
(B) 1 11 _ e ( 11 +1 10 )
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