Solubility of a salt is defined as the maximum amount of a salt which can be dissolved in…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
Solubility of a salt is defined as the maximum amount of a salt which can be dissolved in a given amount of solvent at a particular temperature. Unit of solubility is mole per litre of solution. The solubility of a salt of weak acid with strong base (CH3COOAg) in acidic buffer can be calculated as
\[\begin{array}{l} \begin{array}{l} \mathrm{CH}_{3} \mathrm{COOAg} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COO}^{-}(\mathrm{aq})+\mathrm{Ag}^{+}(\mathrm{aq}) \\ \mathrm{S}-\mathrm{X} \\ \mathrm{CH}_{3} \mathrm{COO}^{-}(\mathrm{aq})+\mathrm{H}^{+} \rightleftharpoons \mathrm{S}=\text { Solubility of salt } \\ (\mathrm{S}-\mathrm{X}) \quad \mathrm{CH}_{3} \mathrm{COOH} \end{array}\\ \text { Dissociation constant of weak acid }\\ \left(\mathrm{K}_{\mathrm{a}}\right)=\frac{(\mathrm{S}-\mathrm{X})\left[\mathrm{H}^{+}\right]}{\mathrm{X}} \end{array}\]
The solubility of LiOH in a solution with pH = 8 is
(Ksp = 1.8 × 10–12)
- 1.8 × 10–18
- 1.8 × 10–6
- 10–6
- 1.8 × 10–4
Answer
(B) 1.8 × 10 –6
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