For Ag 2 CO 3 , K sp = 6.2 × 10 –12 , For AgCl, K sp = 2.8 ×10 –10 . Solid Ag 2 CO 3 and…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
For Ag2CO3, Ksp = 6.2 × 10–12, For AgCl, Ksp
= 2.8 ×10–10. Solid Ag2CO3 and solid AgCl are added to a beaker containing 1.00 M Na2CO3(aq). Under these conditions the [CO32–] = 1.00 M. Calculate the [Cl–] in solution when equilibrium is established.
= 2.8 ×10–10. Solid Ag2CO3 and solid AgCl are added to a beaker containing 1.00 M Na2CO3(aq). Under these conditions the [CO32–] = 1.00 M. Calculate the [Cl–] in solution when equilibrium is established.
- 1.1 × 10–4
- 1.26 × 10–6
- 0.15
- 2.8 × 10–6
Answer
(A) 1.1 × 10 –4
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