General solution of equation 3 cos θ + sin θ = 2 is
Mathematics · JEE Main · NTA Exams — Trigonometry
General solution of equation \(\sqrt{3}\) cos θ + sin θ = \(\sqrt{2}\) is
- nπ ± \(\frac{\pi}{4}+\frac{\pi}{6}\); n ∈ I
- 2nπ ± \(\frac{\pi}{4}+\frac{\pi}{6}\); n ∈ I
- 2nπ ± \(\frac{\pi}{4}-\frac{\pi}{6}\); n ∈ I
- None of these
Answer
(B) 2n π ± 4 + 6 ; n ∈ I
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