Let 0 2 and x = X cos θ + Y sin θ, y = X sin θ – Y cos θ such that x 2 + 4xy + y 2 = aX 2…
Mathematics · JEE Main · NTA Exams — Trigonometry
Let \(0 \leq \theta \leq \frac{\pi}{2}\) and x = X cos θ + Y sin θ,
y = X sin θ – Y cos θ such that x2 + 4xy + y2 = aX2 + bY2, where a, b are constants. Then
y = X sin θ – Y cos θ such that x2 + 4xy + y2 = aX2 + bY2, where a, b are constants. Then
- a = –1, b = 3
- \(\theta=\frac{\pi}{6}\)
- a = 3, b = –1
- \(\theta=\frac{\pi}{3}\)
Answer
(C) a = 3, b = –1
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