If II , are the roots of the equation 6 x^ 2 -5 x+1=0 , then the value of ^ -1 x+ ^ -1 is,
Mathematics · JEE Main · NTA Exams — Trigonometry
If \(\text { II }\), \(\beta\) are the roots of the equation \(6 x^{2}-5 x+1=0\), then the value of \(\tan ^{-1} x+\tan ^{-1} \beta\) is,
- 0
- \(\frac{\pi}{4}\)
- 1
- \(\frac{\pi}{2}\)
Answer
(B) 4
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